Question

If the rms velocity of molecules of a gas in a container is doubled then the pressure will

• A. Become four time
• B. Also get doubled
• C. Be same
• D. Become one half

Answer 1

The correct option is A Become four time

We know that the rms velocity is given as $V_r=\sqrt[2]{2\frac{3P}{\rho }}$

or pressure $P=\frac{\rho V_r^2}{3}$ or simply $P\propto V_a$

So on making $V_a$ , $2$ times the pressure will become $2^2=4$ times.

Option A is correct.