Question

If the roots of $2x^2+3x+p=0$ be equal, then the value of p is :

• A. $\frac{9}{8}$
• B. $\frac{6}{5}$
• C. $\frac{4}{3}$
• D. $\frac{5}{4}$

Answer 1

Answer: (A)

$\frac{9}{8}$

$D=(3^2-4\times 2\times p)=9-8p$

Since, roots are equal $D=0$

$9-8p=0$

$p=\frac{9}{8}$