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Question

If the roots of a1x2+b1x+c1=0 are α1,β1 and those of a2x2+b2x+c2=0 are α2,β2 such that α1β1=1=α2β2 then

A
a1a2=b1b2=c1c2
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B
a1c2=b1b2=c1a2
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C
a1a2=b1b2=c1c2
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D
None of the above
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Solution

The correct option is A a1a2=b1b2=c1c2
Let α,β are common roots of the quadratic equations a1x2+b1x+c2=0

Given, (α1β1=1=α2β2)

Then,
α+β=b1a1,αβ=c1a1

α+β=b2a2,αβ=c2a2

b1a1=b2a2andc1a1=c2a2

a1a2=b1b2anda1a2=c1c2

a1a2=b1b2=c1c2

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