Question

If the roots of a quadratic equation are reciprocals of the roots of $a{x}^2+bx+c=0$, then what will be the coefficient of $c$?

• A. $x$
• B. $x^2$
• C. $-x$
• D. $x^3$

Answer 1

Answer: (B)

$x^2$

We know to find the equation with reciprocal roots, we simply put $\frac{1}{x}$ in the place of $x$.
so, $a(\frac{1}{x}{)}^2+b(\frac{1}{x})+c=0$
On taking LCM we get the required equation
$a+bx+c{x}^2=0$
So the coefficient of $c$ is $x^2$