If the roots of an equation are 23 times the roots of x2 - 9x - 6 - 0- then to find the new equation we will replace x by-

The correct option is B 3x2 We replace x by xk , so here the replacement will be x →x23⇒3x2 . ...

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Solving a Quadratic Equation by Completion of Squares Method

If the roots ...

Question

If the roots of an equation are $\frac{2}{3}$ times the roots of $x^{2} + 9 x + 6 = 0$ , then to find the new equation we will replace $x$ by:

3 x

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\frac{3 x}{2}

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2 x

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\frac{4 x}{5}

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4 x^{7} + 3 x^{6} + 2 x^{5} + 9 x^{4} + 4 x^{3} + x^{2} + 9 x + 9 = 0

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x^{6} - 3 x^{5} + 4 x^{3} + 3 x^{2} + 4 = 0

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