Question

If the roots of equation $3a{x}^2+26x+c=0$ are in the ratio $2:3$.
Then, prove that ${86}^2=25ac$.

Answer 1

$3a{x}^2+26x+c=0$

sum of roots $=5p=\frac{-26}{3a}$

Product $=6P^2=c/3a$

${}^6(\frac{-26}{3a}{)}^2\frac{1}{25}=\frac{c}{3a}$

${86}^2=25ac$