1
Question
If the roots of equation x2−bxax−c = m−1m+1 are equal but opposite in sign, then the value of m will be
If the roots of equation x2−bxax−c = m−1m+1 are equal but opposite in sign, then the value of m will be
Open in App
Solution
The correct option is A
Given equation can be written as
(m+1)x2 - {m(a + b) - (a - b)}x + c(m - 1) = 0
Roots are equal and of opposite sign. so sum of roots is equal to zero.
⇒ 0=m(a+b)−(a−b)⇒m=a−ba+b
Given equation can be written as
(m+1)x2 - {m(a + b) - (a - b)}x + c(m - 1) = 0
Roots are equal and of opposite sign. so sum of roots is equal to zero.
⇒ 0=m(a+b)−(a−b)⇒m=a−ba+b