If the roots of equation x2−bxax−c=m−1m+1 are equal but opposite in sign, the value of m will be
Given equation can be written as
(m + 1)x2 – {m(a + b) – (a – b)}x + c(m – 1) = 0
Roots are equal and of opposite sign.
So sum of roots is equal to zero.
⇒0=m(a+b)−(a−b)⇒m=a−ba+b