Question

If the roots of equation x2−bxax−c=m−1m+1 are equal but opposite in sign, the value of m will be

A

B

C

D

Solution

The correct option is D Given equation can be written as (m + 1)x2 – {m(a + b) – (a – b)}x + c(m – 1) = 0 Roots are equal and of opposite sign. So sum of roots is equal to zero. ⇒0=m(a+b)−(a−b)⇒m=a−ba+bMathematics

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