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Question

If the roots of (z1)25=2ω2(z+1)25( where ω is a complex cube root of unity ) are plotted in the argand plane, they lie in

A
a straight line
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B
a circle
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C
an ellipse
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D
none of these
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Solution

The correct option is B a circle
If z is a root of (z1)25=2ω2(z+1)25, then

(z1z+1)25=2ω2z1z+125=2ω2=2

z1z+1=21/25

As 21/251, we get z lies on a circle.

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