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Question

If the roots of the equation 6x27x+k=0,k>3 are rational, then possible integral value(s) of k is/are

A
1
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B
1,2
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C
2
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D
0,1,2
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Solution

The correct option is D 0,1,2
If roots are rational, then
Δ0 should be a perfect square.
4924k0
k4924

For k=0
Δ=49, which is a perfect square
For k=1,
Δ=25, which is a perfect square.
For k=1,
Δ=73, not a perfect square
For k=2,
Δ=1, which is a perfect square.
For k=2,
Δ=97, not a perfect square

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