Question

If the roots of the equation $a{x}^2+bx+c=0$ are reciprocal of each other, then

• A. $a=b$
• B. $a=c$
• C. $b=c$
• D. $a=0$

Answer 1

The correct option is B $a=c$

$a{x}^2+bx+c=0$

Let roots be $\alpha$ & $\frac{1}{\alpha }$

Product$=\alpha .\frac{1}{\alpha }$

$1=\frac{c}{a}$

So, $a=c$