Question

If the roots of the equation:$a{x}^2+bx+c=0,a>0$ be each greater than unity, then:

• A. $a+b+c>0$
• B. $a-b-c>0$
• C. $a+b+c>0$
• D. $a+b+c=0$
• E. None of these

Answer 1

The correct option is A $a+b+c>0$

Soln:

Both the roots are greater than 1 and a$>$0. So, the graph of the equation will be:

$f\left(x\right)=a{x}^2+bx+c$

$f\left(1\right)>a+b+c>0$

Hence option (a)