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Question

If the roots of the equation ax2+x+b=0 be real and different, then the roots of the equation x24abx+1=0 will be-

A
Rational
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B
Real
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C
Irrational
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D
Imaginary
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Solution

The correct option is D Imaginary
Roots of first equation are real and distinct

14abab1/4

Descriminant of second equation =16ab4

ab1/416ab416ab40

descriminant of the second equation is less than zero

Therefore roots of second equation are imaginary

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