wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the roots of the equation
(c2ab)x22(a2bc)x+(b2ac)=0
be equal, prove that either a=0
or a3+b3+c3+=3abc.

Open in App
Solution

(c2ab)x22(a2bc)x+(b2ac)=0
If the roots be equal, then B24AC=0
4(a2bc)24(c2ab)(b2ac)=0
or [a42a2bc+b2c2][b2c2ab3ac3+a2bc]=0
or a[a3+b3+c3+3abc]=0
Either a0 or a3+b3+c33abc=0.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nature of Roots
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon