If the roots of the equation $x^{2} - 15 - m (2 x - 8) = 0$ are equal, then $m =$

3, - 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3, 5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 3, 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 3, - 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $3, 5$
$x^{2} - 15 - 2 m x + 8 m = 0$
$x^{2} - 2 m x + 8 m - 15 = 0$
Since the roots are equal, hence the discriminant has to be 0.
Or
$B^{2} = 4 A C$
$4 m^{2} = 4 (8 m - 15)$
$m^{2} - 8 m + 15 = 0$
$(m - 5) (m - 3) = 0$
$m = 3, 5$ .

Suggest Corrections

Similar questions

x^{2} - m (2 x - 8) - 15 = 0

m =

\frac{3}{x - 5} + \frac{2 x}{x - 3} = 5

x \neq 3, 5

x^{2} - (m + 1) x + m + 4 = 0

(- \infty, - 3] \cup [5, \infty)

m

x^{2} - m (2 x - 8) - 15 = 0

λ \in R

x^{2} + 2 (a + b + c) x + 3 λ (a b + b c + c a) = 0

Join BYJU'S Learning Program