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Question

If the roots of the equation x2+2bx+c=0 are α and β, then b2c is equal to

A
(αβ)24
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B
(α+β)2αβ
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C
(α+β)2+αβ
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D
(αβ)22+αβ
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E
(α+β)24αβ
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Solution

The correct option is E (α+β)24αβ
Given equation is x2+2bx+c=0

Also α and β are the roots of the given equation.

Thus α+β=2b1=2b

b=α+β2 .......(i)

and α×β=c1=c .......(ii)

Thus b2c=[(α+β2)]2α×β

=(α+β)24αβ

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