Question

If the roots of the equation, $x^2+3x-18=0$ are $-6,3$ then the roots of the equation $2(x^2+3x-18)=0$ are

• A. $-6,6$
• B. $-12,6$
• C. $-6,3$
• D. $3,3$

Answer 1

The correct option is C

$-6,3$

The roots of a quadratic equation do not change when it is multiplied by a constant non-zero real number. So, when the equation $x^2+3x-18=0$ is multiplied by $2,$ the roots still remain the same i.e. $-6,3$