If the roots of the equation x2+ax+b=0 are c and d, then one of the roots of equation x2+(2c+a)x+c2+ac+b=0 is
d−c
Given equation: x2+ax+b=0
Roots are: c and d
c+d=−a and cd=b
⇒c2+ac+b=0 . . . (1)
x2+(2c+a)x+c2+ac+b=0
Using equation (1),
⇒x2+(2c+a)x=0
⇒x[x+(2c+a)]=0
⇒x=−2c−a=−2c+c+d=d−c