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Question

If the roots of the equation x2(p+4)x+2p+5=0 are equal, then the value(s) of p is/are

A
2
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B
1
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C
2
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D
1
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Solution

The correct options are
A 2
C 2
x2(p+4)x+2p+5=0
As roots are equal, so
D=0(p+4)24(2p+5)=0p2+8p+168p20=0p24=0p=±2

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