Question

If the roots of the equation $x^2-(p+4)x+2p+5=0$ are equal, then the value(s) of $p$ is/are

• A. $-2$
• B. $2$
• C. $1$
• D. $-1$

Answer 1

Answer: (A), (B)

$2$

$x^2-(p+4)x+2p+5=0$
As roots are equal, so
$D=0\Rightarrow (p+4{)}^2-4(2p+5)=0\Rightarrow p^2+8p+16-8p-20=0\Rightarrow p^2-4=0\Rightarrow p=\pm 2$