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Question

If the roots of the equation x312x2+39x28=0 are in A.P., then their common difference will be


A

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B

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C

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D

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Solution

The correct option is C


Let a – d, a, a + d be the roots of the equation x312x2+39x28=0
Then (ad)+a+(a+d)=12 and (ad)a(a+d)=28
3a=12anda(a2d2)=28
a=4anda(a2d2)=28
16d2=7d=±3.


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