If the roots of the equation x3−12x2+39x−28=0 are in A.P., then their common difference will be
Let a – d, a, a + d be the roots of the equation x3−12x2+39x−28=0
Then (a−d)+a+(a+d)=12 and (a−d)a(a+d)=28
⇒3a=12anda(a2−d2)=28
⇒a=4anda(a2−d2)=28
⇒16−d2=7⇒d=±3.