If the roots of the equation x3−9x2+23x−15=0 are the first three terms of an A.P, then the sum of first 20 terms of the A.P. can be
A
400
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B
280
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C
−400
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D
−280
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Solution
The correct options are A400 D−280 Let roots are a−d,a,a+d ⇒(a−d)+a+(a+d)=9⇒a=3⇒(a−d)a(a+d)=15⇒d=±2⇒Roots are1,3,5whend=2⇒Roots are5,3,1whend=−2When,a=1andd=2S20=202[2×1+19×2]=400When,a=5andd=−2S20=202[2×5+19×(−2)]=−280