if the roots of the equation x2 -2mx +m2 - 1 =0 lie in the interval (-2,4) then,
a) m ~ (-1,3) b) m~(1,5)
c) m~(-3,1) d) m~(-1.5)
where ~ stand for "belongs to".
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Solution
If roots ax2+bx+c=0 lie between k1 and k2 then of (k1) > 0, of (k2) > 0 and k1 < −b2a < k2 f(-2)>0, f(4) > 0 and -2 <m<4 ⇒4+4m+m2−1>0, 16−8m+m2−1>0 and -2<m<4 ⇒m2+4m+3>0,m2−8m+15>0 and -2<m<4 ⇒ (m+1)(m+3) > 0, (m-3)(m-5) > 0 and -2<m<4 ⇒ -1<m<3 [combining all]