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Byju's Answer
Standard X
Mathematics
Nature of Roots
If the roots ...
Question
If the roots of the quadratic equation
p
(
q
−
r
)
x
2
+
q
(
r
−
p
)
x
+
r
(
p
−
q
)
=
0
are equal,
Show then
1
p
+
1
r
=
2
q
=
m
q
Find m.
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Solution
p
(
q
−
r
)
x
2
+
q
(
r
−
p
)
x
+
r
(
p
−
q
)
=
0
D
=
0
∴
the root are equal
D
=
b
2
−
4
a
c
⇒
(
q
(
r
−
p
)
)
2
−
4
(
p
(
q
−
r
)
)
(
r
(
p
−
q
)
)
)
=
0
⇒
q
2
(
r
2
+
p
2
−
2
p
r
)
−
4
(
(
p
q
−
p
r
)
(
p
r
−
q
r
)
)
=
0
⇒
q
2
(
r
2
+
p
2
−
2
p
r
)
−
4
(
p
2
q
r
−
p
q
2
r
−
p
2
r
2
+
p
q
r
2
)
=
0
⇒
q
2
r
2
+
p
2
q
2
−
2
p
q
2
r
−
4
p
2
q
r
+
4
p
q
2
r
+
4
p
2
r
2
+
4
p
q
r
2
=
0
⇒
q
2
r
2
+
p
2
q
2
+
4
p
2
r
2
−
4
p
2
q
r
+
2
p
q
2
r
+
4
p
q
r
2
=
0
⇒
(
p
q
+
q
r
−
2
p
r
)
2
=
0
[
∵
(
a
+
b
+
c
)
2
=
a
2
+
b
2
+
c
2
−
2
a
b
+
2
b
c
+
2
a
c
]
⇒
p
q
+
q
r
=
2
p
r
Dividing by
p
=
q
r
1
r
+
1
p
=
2
q
Hence ,
m
=
2
Suggest Corrections
2
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−
r
)
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)
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q
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=
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q
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q
)
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