If the roots of the quadratic equation x2+px+q=0 are tan30∘ and tan15∘, respectively then the value of 2+q−p is
A
0
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B
1
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C
2
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D
3
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Solution
The correct option is A 3 tan30+tan15=−b/a=−p...(i) tan30tan15=c/a=q...(ii) tan45=1=tan30+tan151−tan30tan15 =−p1−q after substitution from equation i and ii. Therefore 1−q=−p 1=q−p q−p+2=1+2=3 Answer is 3