If the roots of x2+8x+15=0 are -3 and -5, then the roots of 6x2+48x+90=0 are .
A
3 and 5
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B
-3 and -5
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C
-18 and -30
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D
-30 and -50
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Solution
The correct option is B -3 and -5 Given, the roots of x2+8x+15 = 0 are -3 and -5.
The equation 6x2+48x+90 = 0 can be written as
6×(x2+8x+15) = 0 ⇒x2+8x+15 = 0.
Hence, the roots of 6x2+48x+120 = 0 are -3 and -5.
The roots of a quadratic equation do not change when it is multiplied by a constant non-zero real number.