Question

If the roots ofx^2 +mx + 12=0 are in the ratio 1:3. find 'm'

Answer 1

Let the roots of the equation be 'a' and 'b'
a/b=1/3
therefore
b=3a
product of the roots=ab=constant /coeff of x sq.
=ab=12/1
3a^2 = 12
Or a = +/- 2
wen a=2,b=6
wen a=-2,b=-6
sum of the roots= -coeff of x/coeff of x sq.
=a+b=-m/1
=+/-8
ans m=+/-8