Question

If the scalar and vector products of two vector are $4\sqrt{3}$ and $144$ respectively, what is the angle between the two vectors?

• A. tan${}^{-1}\left(12\sqrt{3}\right)$
• B. tan${}^{-1}(\frac{38}{\sqrt{3}})$
• C. tan${}^{-1}(\frac{\sqrt{3}}{12})$
• D. tan${}^{-1}\left(36\right)$

Answer 1

The correct option is A tan${}^{-1}\left(12\sqrt{3}\right)$

Magnitude of vector product/scalar product $=tan\theta$
Thus, $tan\theta =\frac{144}{4\sqrt{3}}$
Thus, $\theta =ta{n}^{-1}$ $12\sqrt{3}$