Question

If the sector of a circle of diameter $14cm$ subtends an angle of ${30}^{\circ }$ at the centre, then its area is

• A. $49\pi$
• B. $\frac{49\pi }{12}$
• C. $\frac{242}{3\pi }$
• D. $\frac{121}{3\pi }$

Answer 1

Answer: (B), (D)

$\frac{49\pi }{12}$
$\frac{121}{3\pi }$

Area of a sector $=\frac{\theta }{{360}^0}\times \pi r^2=\frac{30}{360}\times \pi (7{)}^2=\frac{49\pi }{12}$

Also,

$\frac{121}{3\pi }=\frac{121\times 7}{3\times 22}=\frac{49\times 22}{12\times 7}=\frac{49\pi }{12}$