Question

If the separation between the plates of'.a capacitor is 5 mm,then the area of the plate of a 3 F parallel plate capacitor is:

• A. $4.259\times {10}^9{m}^2$
• B. $1.964\times {10}^9{m}^2$
• C. $12.81\times {10}^9{m}^2$
• D. $1.694\times {10}^9{m}^2$

Answer 1

The correct option is D $1.694\times {10}^9{m}^2$

The expression of parallel plate capacitor is given by $C=\frac{A{ϵ}_0}{d}$

so area of plate , $A=\frac{Cd}{{ϵ}_0}=\frac{3\times (5\times {10}^{-3})}{8.85\times {10}^{-12}}=1.694\times {10}^9{m}^2$