If the set of factors of a whole number 'n' including 'n' itself but not '1' is denoted by $F (n), F (16) \cap F (40)$ = $F (x)$ then 'x' is

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Solution

The correct option is B
8

F(16)={2,4,8,16}

F(40)={2,4,5,8,10,20,40}

F(16) $\cap$ F(40)={2,4,8}=F(8)

F(X)=F(8)⟹x=8

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