If the set of factors of a whole number $n$ including $n$ itself but not $1$ is denoted by $F (n)$ and $F (16) \cap F (40) = F (X)$ , then $X$ is

4

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8

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6

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10

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Solution

The correct option is B $8$
$F (16) = {2, 4, 8, 16}$
$F (40) = {2, 4, 5, 8, 10, 20, 40}$
$F (16) \cap F (40) = {2, 4, 8} = F (8)$
$∴ x = 8$

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