If the sets A and B are defined as A - x- y - y - 1-x- 0 - x - R B - x- y - y - -x- x - R- then

The correct option is D Since y = nbsp; nbsp; 1/x, y = x meet when x = nbsp; nbsp; 1/x nbsp;⇒ nbsp;x^2 = 1, which does not give any real value ...

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How to Find the Inverse of a Function

If the sets A...

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If the sets A and B are defined as

A = {(x, y) : y = $\frac{1}{x}$ , 0 ≠ x ∈ R}

B = {(x, y) : y = -x, x ∈ R}, then

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None of these

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If sets $A$ and $B$ are defined as
$A = {(x, y) | y = \frac{1}{x}, x \neq 0, x \in R},$
$B = {(x, y) | y = - x, x \in R},$ then

A

B

A = {(x, y) : y = \frac{1}{x}, 0 \neq x \in R}

B = {(x, y) : y = - x, x \in R}

If the sets $A$ and $B$ are defined as

$A = {(x, y) : y = \frac{1}{x}, x \in R - {0}}$

$B = {(x, y) : y = - x, x \in R}$ , then

If the sets A and B are defined as

A = {(x, y) : $y = \frac{1}{x}$ , 0 ≠ x ∈ R}

B = {(x, y) : y = -x, x ∈ R}, then

If the sets A and B are defined as A = {(x, y) : y = $e^{x}$ , x ∈ R};

B = {(x, y) : y = x, x ∈ R}, then

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