If the sets A and B are defined as A - x - y - y -1- x - x - 0- and -x - R B-x- y- y-x- x - R- thenA- A - B-AB- A - B-BC- A - B-D- None of these

The correct options are C D None of these Since, y = nbsp; nbsp; 1/x y = x The both lines meet when x = nbsp; nbsp;1/x nbsp;⇒ nbsp;x^2 = 1, wh ...

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Eccentricity

If the sets A...

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If the sets A and B are defined as

A = {(x, y) : y = $\frac{1}{x}$ , x≠ 0 and x ∈ R}

B = {(x, y) : y = -x, x ∈ R}, then

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None of these

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Similar questions

If the sets A and B are defined as

A = {(x, y) : y = $\frac{1}{x}$ , 0 ≠ x ∈ R}

B = {(x, y) : y = -x, x ∈ R}, then

A = \{(x, y) : y = \frac{1}{x}, 0 \neq x \in R\}, B = \{(x, y) : y = - x, x \in R\},

If sets A and B are defined as

A = ${(x, y) : y$ = $e^{x}, x \in R}$

B = ${(x, y) : y$ = $x, x \in R}$ , then

If the sets A and B are defined as A = {(x, y) : y = $e^{x}$ , x ∈ R};

B = {(x, y) : y = x, x ∈ R}, then

A

B

A = {(x, y) : y = \frac{1}{x}, 0 \neq x \in R}

B = {(x, y) : y = - x, x \in R}

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