If the shearing stress between the horizontal layers of water in a river is 1-5 mN- m2 and - water- 1-10-3Pa-s - The velocity gradient is-

The correct option is C 1.5 Shearing stress #160; =ηdvdy=1.5 × 10^ 3 N /m^2 ⇒ 1 × 10^ 3dvdy=1.5 × 10^ 3 ⇒dvdy=1.5 s^ 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Physics

Viscosity

If the sheari...

Question

If the shearing stress between the horizontal layers of water in a river is $1.5 m N / m^{2}$ and $η_{w a t e r} = 1 \times 10^{- 3} P a - s$ , The velocity gradient is:

1.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $1.5$
Shearing stress $= η \frac{d v}{d y} = 1.5 \times 10^{- 3} N / m^{2}$

$\Rightarrow 1 \times 10^{- 3} \frac{d v}{d y} = 1.5 \times 10^{- 3}$

$\Rightarrow \frac{d v}{d y} = 1.5 s^{- 1}$

Suggest Corrections

Similar questions

Q. The velocity of water in a river is

18 k m p h

near the surface. If the river is

4 m

deep, the shearing stress between horizontal layers of water in Nm

^{- 2}

(η_{w a t e r} = 1 \times 10^{- 3} p a . s)

The velocity of water in a river is 18 km h^-1 near the surface. If the river is 5 m deep, find the shearing stress between the horizontal layers of water. The coefficient of viscosity of water = 10^-2 poise.

Q. The velocity of water in the river is

9 k m / h r

of the upper surface. The river is

10

m deep. If the coefficient of viscosity of water is

10^{- 2}

poise then the shearing stress between horizontal layers of water is.

Q. A river

10 m

deep is flowing at

5 m / s

. The shearing stress between horizontal layers of the river is

(η = 10^{- 3} S I u n i t s)

Join BYJU'S Learning Program

If the shearing stress between the horizontal layers of water in a river is 1.5mN/m2 and ηwater=1×10−3Pa−s , The velocity gradient is:

The correct option is C 1.5Shearing stress =ηdvdy=1.5×10−3N/m2⇒1×10−3dvdy=1.5×10−3⇒dvdy=1.5 s−1

If the shearing stress between the horizontal layers of water in a river is $1.5 m N / m^{2}$ and $η_{w a t e r} = 1 \times 10^{- 3} P a - s$ , The velocity gradient is:

The correct option is C $1.5$
Shearing stress $= η \frac{d v}{d y} = 1.5 \times 10^{- 3} N / m^{2}$

$\Rightarrow 1 \times 10^{- 3} \frac{d v}{d y} = 1.5 \times 10^{- 3}$

$\Rightarrow \frac{d v}{d y} = 1.5 s^{- 1}$