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Question

If the shortest distance between the lines x33=y81=z31 and x+33=y+72=z64 is λ30 units, then the value of λ is .....................

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is C 3
We have a1=3^i+8^j+3^k, b1=3^i^j+^k
a2=3^i7^j+6^k and b2=3^i+2^j+4^k
Now b1×b2=∣ ∣ ∣^i^j^k311324∣ ∣ ∣=6^i15^j+3^k
b1×b2=62+152+32=330
a1a2=6^i+15^j3^k
Therefore shortest distance between both the lines is
d=(a1a2)×(b1×b2)b1×b2=62+152+32330=330
Hence, λ=3

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