If the shortest distance between the lines x−33=y−8−1=z−31 and x+3−3=y+72=z−64 is λ√30 units, then the value of λ is .....................
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is C3 We have →a1=3^i+8^j+3^k, →b1=3^i−^j+^k →a2=−3^i−7^j+6^k and →b2=−3^i+2^j+4^k Now b1×b2=∣∣
∣
∣∣^i^j^k3−11−324∣∣
∣
∣∣=−6^i−15^j+3^k ∣b1×b2∣=√62+152+32=3√30 a1−a2=6^i+15^j−3^k Therefore shortest distance between both the lines is d=∣(a1−a2)×(b1×b2)∣b1×b2∣∣=62+152+323√30=3√30 Hence, λ=3