If the side of one square is the diagonal of a second square, what is the ratio of the area of the first square to the area of the second?

\sqrt{2}

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2

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1 / 2

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2 \sqrt{2}

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Solution

The correct option is B $2$
In the adjoining figure, if $s$ is the length of a side of the first square, then $s / \sqrt{2}$ is the length of a side of the second. Thus the ratio of the areas is $s^{2} / (s / \sqrt{2})^{2} = 2$

∴ (B) is the correct option.

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If the side of one square is the diagonal of a second square, what is the ratio of the area of the first square to the area of the second?

The correct option is B 2In the adjoining figure, if s is the length of a side of the first square, then s/√2 is the length of a side of the second. Thus the ratio of the areas is s2/(s/√2)2=2 ∴ (B) is the correct option.

The correct option is B $2$
In the adjoining figure, if $s$ is the length of a side of the first square, then $s / \sqrt{2}$ is the length of a side of the second. Thus the ratio of the areas is $s^{2} / (s / \sqrt{2})^{2} = 2$

∴ (B) is the correct option.