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Question

If the side of the triangle ABC are 6,8,10 units, then find the radius of circumcircle is

A
4
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B
3
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C
6
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D
5
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Solution

The correct option is B 5
REF.Image.
given : sides of Δ ABC : 6,8,10
[62+82=102]
(AB)2+(BC)2=(AC)2
ΔABC is right triangle.
radius of circum circle of a right triangle=[hypotenuse2]
radius of circum circle of ABC=AC2=5 units.
The radius of circum circle of ΔABC is 5 units.

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