If the sides BA and DC of quadrilateral ABCD are produced as shown in the given figure. then Refer Image
A
x + y = a + b
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B
x - y = a - b
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C
x−y2=a−b
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D
None of these
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Solution
The correct option is C x + y = a + b For Triangle CBD, ∠a is exterior angle. So, ∠1+∠2=∠a -----------eq1 & For Triangle ABD, ∠b is exterior angle. So, ∠3+∠4=∠b-----------eq2 adding eq 1 and eq 2 ∠1+∠2+∠3+∠4=∠a+∠b (As ∠1+∠4=∠x & ∠3+∠2=∠y) So, ∠x+∠y=∠a+∠b Answer (a) x + y = a + b