If the sides of 4 squares are 4 cm , 3 cm , 2 cm and 1 cm respectively, what is the mean of their areas?

8 $c m^{2}$

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7.5 $c m^{2}$

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8.5 $c m^{2}$

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7 $c m^{2}$

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Solution

The correct option is B
7.5 $c m^{2}$

Area of a square = Side $\times$ Side

Threfore, area of the 4 squares = 16 , 9 , 4 and 1 $c m^{2}$ respectively

Mean of the areas = $\frac{S u m o f a r e a s}{4}$

= $\frac{16 + 9 + 4 + 1}{4}$

= $\frac{30}{4}$

= 7.5 $c m^{2}$

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If the sides of 4 squares are 4 cm , 3 cm , 2 cm and 1 cm respectively, what is the mean of their areas?

The correct option is B 7.5 cm2 Area of a square = Side×Side Threfore, area of the 4 squares = 16 , 9 , 4 and 1 cm2 respectively Mean of the areas = Sum of areas4 = 16+9+4+14 = 304 = 7.5 cm2

The correct option is B
7.5 $c m^{2}$

Area of a square = Side $\times$ Side

Threfore, area of the 4 squares = 16 , 9 , 4 and 1 $c m^{2}$ respectively

Mean of the areas = $\frac{S u m o f a r e a s}{4}$

= $\frac{16 + 9 + 4 + 1}{4}$

= $\frac{30}{4}$

= 7.5 $c m^{2}$