If the sides of a rectangle are 6xz+4y−2xy−3x+6 units and xy−2x+4xz−9 units, then its perimeter is ___.
A
20xz+2xy+8y+10x−6
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B
20xz−2xy+8y−10x−6
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C
10xz−xy+4y−5x−3
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D
20xz−xy+4y−10x−6
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Solution
The correct option is B20xz−2xy+8y−10x−6 Let the length and the breadth of the rectangle be 6xz+4y−2xy−3x+6 units xy−2x+4xz−9 units respectively. Perimeter of the rectangle = 2(length + breadth) =2[(6xz+4y−2xy−3x+6)+(xy−2x+4xz−9)] Grouping the like terms together, we get Perimeter=2[(6xz+4xz)+(−2xy+xy)+(4y)+(−3x−2x)+(6−9)] =2(10xz−xy+4y−5x−3) =20xz−2xy+8y−10x−6 Hence, the perimeter of the rectangle is 20xz−2xy+8y−10x−6 units.