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Question

If the sides of a rectangle are 6xz+4y2xy3x+6 units and xy2x+4xz9 units, then its perimeter is ___.

A
20xz+2xy+8y+10x6
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B
20xz2xy+8y10x6
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C
10xzxy+4y5x3
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D
20xzxy+4y10x6
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Solution

The correct option is B 20xz2xy+8y10x6
Let the length and the breadth of the rectangle be 6xz+4y2xy3x+6 units xy2x+4xz9 units respectively.
Perimeter of the rectangle = 2(length + breadth)
=2[(6xz+4y2xy3x+6)+(xy2x+4xz9)]
Grouping the like terms together, we get
Perimeter=2[(6xz+4xz)+(2xy+xy)+(4y)+(3x2x)+(69)]
=2(10xzxy+4y5x3)
=20xz2xy+8y10x6
Hence, the perimeter of the rectangle is 20xz2xy+8y10x6 units.

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