Question

If the sides of a right angle triangle forms an AP, then 'sin' of the acute angles are

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

$\text{Let ABC be a right angled triangle, where}\angle B={90}^0\text{and sides forming an AP are a - x, a, a + x}$

$\text{Clearly,}(a+x{)}^2=a^2+(a-x{)}^2\Rightarrow a=4x\therefore sinA=\frac{4}{5},sinC=\frac{3}{5}$