If the sides of a triangle are (a - 3ab + 8), (4a + 5ab - 3) and (6 - 3a + 4ab) units, then its perimeter is ____.

(8a + 6ab + 11) units

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(2a + 6ab + 1) units

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(4a + 6ab + 11) units

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(2a + 6ab + 11) units

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Solution

The correct option is D (2a + 6ab + 11) units
Given,
Sides of the triangle = (a - 3ab + 8), (4a + 5ab - 3) and (6 - 3a + 4ab) units.

Perimeter of a triangle = Sum of all three sides
= (a - 3ab + 8) + (4a + 5ab - 3) + (6 - 3a + 4ab)
Grouping the like terms,
= (a + 4a - 3a) + (- 3ab + 5ab + 4ab) + (8 - 3 + 6)
= (2a + 6ab + 11) units
Hence, the perimeter of the triangle is (2a + 6ab + 11) units.

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