If the sides of a triangle are a, b and c. Then, what is the semi perimeter of the triangle?

(a+b+c)/2

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(a+b+c)

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(a+b+c)/4

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$\frac{a + b + c}{3}$

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Solution

The correct option is A
(a+b+c)/2

If the sides of a triangle are a, b and c. Then the semi perimeter of the triangle = $\frac{a + b + c}{2}$ .

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Similar questions

\frac{(s - a) + (s - b) + (s - c)}{(\frac{4}{3} s - \frac{5}{4} a) + (\frac{4}{3} s - \frac{5}{4} b) + (\frac{4}{3} s - \frac{5}{4} c) ?}

If a,b,c are three sides of the triangle, then the perimeter of the triangle is

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\frac{2 a}{b + c - a} + \frac{2 b}{c + a - b} + \frac{2 c}{a + b - c}

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A B C

c = 2 a

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The area of a triangle, with sides a, b, c and semi-perimeter s, is:

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