The correct option is C becomes 4 times
Let, the original sides be a,b and c.
s=12(a+b+c)
and area of the triangle =√s(s−a)(s−b)(s−c)
For the new triangle, the sides are 2a, 2b, 2c.
Then, S=12(2a+2b+2c)=a+b+c=2s.
∴ Area of new triangle
=√S(S−2a)(S−2b)(S−2c)=√2s(2s−2a)(2s−2b)(2s−2c)=√16s(s−a)(s−b)(s−c)=4√s(s−a)(s−b)(s−c)
=4× (area of original triangle)