If the sides of a triangle are in G.P., and its larger angle is twice the smallest, then the common ratio r stisfies the inequality
Let the sides of the triangle be a/r, a and ar,with a>0 and r> 1. Let ∝ be the smallest angle, so that the largest angle is 2∝ . Then ∝ is opposite to the side a/r , and 2∝ is positive to the side ar. Applying sine rule, we get
a/rsin α=arsin 2α
⇒sin 2αsin α
⇒2 cos α=r2
⇒r2<2
⇒r<√2