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Question

If the sides of a triangle are in the ratio 1:3:2, then the angles of the triangle are in the ratio

A
1 : 2 : 3
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B
1 : 3 : 2
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C
3:2:1
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D
1:2:3
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Solution

The correct option is A 1 : 2 : 3
Let ABC be a Δ such that a:b:c=1:3:2, we have
sin Aa=sin Bb=sin Ccsin A1=sin B3=sin C2sin A12=sin B32=sin C1
=sin Asin(π6)=sin Bsin(π3)=sin Csin(π2)
A:B:C=π6:π3:π2=A:B:C=1:2:3

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