Question

If the sides of a triangle are in the ratio $2:\sqrt{6}:(\sqrt{3}+1)$, then the largest angle of the triangle will be

• A. ${60}^{\circ }$
• B. ${75}^{\circ }$
• C. ${90}^{\circ }$
• D. ${120}^{\circ }$

Answer 1

The correct option is B

${75}^{\circ }$

$cos\theta =\frac{4+6-(\sqrt{3}+1{)}^2}{2.2\sqrt{6}}\Rightarrow \theta ={75}^{\circ }.$