If the sides of a wall having thermal conductivity K are maintained at temperatures of T1 and T2, the temperature as a function of x can be written as T(x)=(T2−T1)(xL)+T1 Find the heat flux through the wall. Take T1>T2
A
KT1L
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B
KT2L
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C
K(T1−T2)L
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D
0
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Solution
The correct option is CK(T1−T2)L Heat flux is the rate of heat transfer per unit area, ⇒˙q=˙QA=−KdTdx ⇒˙q=−Kddx[(T2−T1)xL+T1] ∴˙q=K(T1−T2)L